Chapter 8 Energy Transport
Background
• Chapter 5 dealt with how the neutron population varies in time
• Chapter 6 and 7 dealt with the s patial distribution of neutrons in the core
– It was determine that a critical reactor could operate at any power level and that the equilibrium would hold
• N o t en ti re l y t rue !
• A t high power levels, temperature changes will create important transients
Objectives
• Find simple expressions to approximate fuel temperature and coolant temperature in a reactor
– S teady-state temperatures
– Transients
• D etermine temperature effect on reactivity
C o r e Power D e n s i t y
P''' = P / V
• P ’’’ is the power density
• P i s the t o t a l c o r e power
• V is the core volume
P o w e r Peaking F a c t o r
F q = P m '' ' ax / P'''
• F q is the power peaking factor
• P ’’’ max i s the m a x i m u m p o w e r d e n s i t y i n the core
P = P ' m ''
ax V
F q
• We can combine the two p revious e q uations and find the above relation
• Cores are designed to operate at a given power P
– Maximizing the ratio P’’’max / Fq will allow for smaller r e a c t o r d e s i g n a t g iven p o w e r P
• Reduces construction cost
– Main job of reactor physicist is to maximize this ratio
• Control r ods
• New designs
• Varying enrichment
• …
• P ’’’ max depends primarily on material properties
Temperature and pressure that can be tolerated by fuel, coolant, structure
• Fq can be lowered by playing with enrichment loading, position of control
rods ,
poisons ,
reflector , …
f r (r)
f q (r ,z) = f r (r)f z (z)
f z (z)
For a uniform bare reactor – F q = F r F z
From chapter 7, we’ve seen the solution for such a reactor
– F r = 2.32
– F z = 1.57
More complicated geometries will have higher peaking due to local variations
Image by MIT OpenCourseWare.
Simple heat transfer on fuel e l ement
• Define q ’ has the linear heat rate (kW/m)
– T hermal power produced per unit length
– P ’’’ = q ’ / A cell element
where A cell is the area of the fuel
q’ = PF q A cell / V = PF q / NH N: Number of fuel pins
H: Height of the core
Steady - s t a t e temperatures
• T e m p e r a t u r e d r o p f r o m f u e l t o coolant i s proportional to linear heat rate
T fe ( r , z ) - T c ( r ,z ) = R f ' e q ' ( r ,z )
– R’ fe is the fuel element thermal resistance, details of which are found in Appendix D
• f unc ti on o f th e th erma l con d uc ti v i t y o f th e f ue l an d
the cladding as well as the heat transfer coefficient
• If we average over the volume
T f - T c = R f P
w h ere
NH
R f = 1 R ' fe
It should be noted that w h e n a v e r a g i n g q ’ using the previous relation q’ = PF q / NH, we
must note that the avera g e core factor is 1.
p eakin g
We know Rf and P, but we need more information to evalute Tf and Tc
Coolant heat balance
Outlet temperature = T 0
W ch c p [ T 0 ( r ) - T i ] =
H/ 2
-H/ 2
q' ( r , z' ) dz'
_ Replacing q' and solving for T 0
Flow rate = W ch
T 0 ( r ) =
1 P Wc p NH
f r ( r )
H/ 2
-H/ 2
f z (z) dz + T i
_ Define total core flow rate
W = NW ch
Inlet temperature = T i
Image by MIT OpenCourseWare.
• We get
Wc
T 0 ( r ) =
1 Pf r ( r ) + T i p
• If we average radially
T 0 =
1 P + T i p
Wc
• Average coolant temperature
T c =
1 ( T o + T i )
2
• We can than get an expression for the coolant
tem p erature
1 P + T
T c = i
2Wc p
• And we can replace it in our previous expression
2Wc p
T f = ( R f + 1
P + T i
Fuel Thermal transients
• If c o o l i n g is t u r n e d o f f , w e c a n approximate that the fuel will heat up adiabatically
M f c f
d T f ( t ) = P ( t ) - 1 [ T f ( t ) - T c (t)]
R
dt
f
M f is the total fuel mass c f is the fuel specific heat
• B o u n d i n g c a se s
– Steady-state d/dt =0 P = ( T f - T c )/ R f
dt
– N o c o o l i n g ( R f tends to infinity) M f c f d T f ( t ) = P ( t )
• All the power stays in the fuel, fuel temperature increases and can eventuall y lead to meltin g
• More convenient form
d T f ( t ) = 1 P ( t ) - 1 [ T f ( t ) - T c ( t )]
dt M f c f
IJ i s t h e core t h erm a l t i me constant
Coolant thermal transient
• C o n s e v a t i o n e q u a t i o n in the c o o l a n t
M c c p
d T c ( t ) = 1
dt
R
f
[ T f ( t ) - T c ( t )] - 2 Wc p [ T c ( t ) - T i ]
R
Heating term 1 [ T f ( t )- T c ( t )]
f
Cooling term 2 Wc p [ T c ( t )- T i ]
• W e ca n r e writ e h as
c
d T ( t ) = 1
dt '
[ T ( t ) - T ( t )] - 1
f c
''
[ T c ( t ) - T i ]
where
' =
M c c p
M f c f
and
'' =
M c c p
2 Wc p
• C oolant usuall y follows fuel surface transient quite rapidly
– W e c a n ignore the energy storage t e r m of the
coolant equation
T c ( t ) =
1 1 + 2 R f Wc p
[2 R f Wc p T i + T f ( t )]
• C ombining with the fuel transient expression
f
d T ( t ) =
dt
1 P ( t ) - 1
M f c f ~
[ T f
( t ) - T i ]
Chapter 9 Reactivity Feedback
Background
• Temperature increase w ill create feedback mechanisms in the reactor
– Do pp ler broadenin g
– T hermal expansion
– Densit y cha n g es which will induce s p ectral shifts
• T hese changes will impact the reactivity, thus causing transients
Reactivity Coefficients
• D y n a m i c r e a c t i v i t y was d e f i n e d b y
( t ) = k ( t ) - 1
k ( t )
• We can relate a change in reactivity to a chan g e in k
dp = dk/k 2 ~
dk/k
= d (ln k )
• The advantage is that we change a multiplication of terms into a sum of terms
F u e l Temperature C oefficient
• D oppler broadening of the resonance capture cross-section of U-238 is the dominant effect in LWR reactors
– Lots of U-238 (red) present
– S imilar effect with Th-232 (green)
Image removed due to copyright restrictions.
Fuel Temperature C oefficient
• E ffect is felt in resonance esca p e p robabilit y (p)
• N o effect on ε ,because …
• M inor effect on η and f
– E specially in the presence of Pu-239
• D oppler effect arises from the temperature d epen d ence o f th e cross-sec ti on on th e re l a ti ve speed between neutron and nucleus
– Resonances are s meared in energy has temperature increases.
– Thermal resonances are more important
F u e l Temperature C o e fficient
• W e c a n a p p r o x i m a t e i t b y
f =
1 k ~
1 p
k T f
p T f
• Y ou can eva l ua t e i t us i ng f ormu l as f rom Chapter 4 used to determine p (see book)
• O r, you can a l so run s i mu l a t i ons a t different fuel temperatures and compare the e s t i m a t e o f the e i g e n v a l u e
M o d e r a t o r Temperature Coefficient
• We s e e k to evaluate
m = 1 k
k T m
• T he biggest impact of the moderator temperature comes f r o m a s s o c i a t e d c h a n g e s in density
– A s temperature increases, moderator ( and coolant ) will see a decrease in their density
• Less water molecules, means less moderation, leading to a s p e c t r a l s h i f t
M o d e r a t o r Temperature Coefficient
• D ecrease in slowin g down efficienc y will lead to an increase in resonance absorption
– V alue of p will decrease
• Lower coolant density will also have an impact on the thermal utilization (f)
– V alue of f will increase
• F a s t f ission will increase slightly, but e ff ect is negligible
• The combine effect is usually negative , but in
some reactors with solid moderators (i.e. graphite), the coefficient might be positive over certain temperature ranges .
Coolant Void Reactivity Coefficient
• In LWRs and BWRs, this coefficient is alwa y s ne g ative
– C oolant and moderator are the same, thus losing the coolant also implies loosing all the moderation
• In CANDU and RBMK , this coefficient is p ositive
– Loosing the coolant as very little impact on the moderation
• C auses slight increase in fast fission
• C auses sli g ht increase in resonance esca p e p robabilit y
– Before Chernobyl, void reactivity coefficient of RBMK was 4.7 beta, after re-design it was lowered to 0.7 beta
– C ANDU have a very small positive reactivity coefficient that can be controlled easily
Fast Reactor Coefficients
• Leakage plays a more important role in fast reactor transients
– D ecreasing density will make the spectrum harder
• Larger value of η , thus increase in k
– Migration length would also increase
• More leakage , th u s decreasing k
– Overall effect is usually positive
• Doppler effect is smaller in m agnitude
– Thermal resonances are more affected
I s o t h e r m a l T emperature Coefficient
• In man y reactors, the entire core is brou g ht ver y slowly from room temperature to the operating inlet coolant temperature
– R e a c t o r a t l o w p o w e r
– E xternal heat source
– D ecay heat
• R easona b l e approx i ma ti on i s t o assume th a t th e core behaves isothermally
T f = T c = T i
• We can thus define the isothermal temperature
coefficient
d fb 1 k 1 k
= = +
T = f c
T dT k T f k T c
Temperature D e f e c t
• This coefficient a l l o w s u s t o e s t i m a t e the amount of reactivity needed to maintain c r i t i c a l i t y a t h i g h t e m p e r a t u r e ( h o t z e r o power)
• T h i s r e a c t i v i t y i s o b t a i n e d b y i n t e g r a t i n g the isothermal temperature coefficient from r o o m t e m p e r a t u r e t o hot t e m p e r a t u r e
D T = T i T ( T ) dT
T r
P o w e r c o e f f i c i e n t
• A far m o r e u s e f u l c o e f f i c i e n t , i t t a k e s i n t o account impact of temperature changes when r e a c t o r i s o p e r a t i n g a t f u l l power
d fb
1 k
dT f 1 k
dT c
P = dP
=
k T f
dP + k
T c dP
• If we assume that power changes are slow compared to the time required for heat removal, we can use the steady-state temperature profiles from Chapter 8 and derive them with respect to Power
T c =
2 1 P + T i
d T c = 1
Wc p
dP 2 Wc p
T f = R f + 2
1 P + T i d T f = R f + 1
( Wc p ) d P 2 Wc p
P o w e r c o e f f i c i e n t
• T h e p o w e r coefficient i s t h u s e x p r e s s e d i n
terms of both the fuel coefficient and the moderator coefficient
2 Wc p
k
T f
2 Wc p
k
T c
P = ( R f + 1 ) 1 k + 1 1 k
P = R f f + (2 Wc p ) -1 ( f + c )
• T h u s , a s p o w e r i s i n c r e a s e d , p o s i t i v e reactivity is required to overcome negative c o e f f i c i e n t s a n d m a i n t a i n c r i t i c a l i t y
P o w e r D e f e c t
• A s p o w e r i n c r e a s e s t o its o p e r a t i n g level, additional negative reactivity is introduced b y an increase in tem p erature
• We can evaluate the power defect by the followin g
D p = T f ( p )
T i f
( T f
) dT f +
T c ( p ) e ( T c ) dT c
T i
where T f (P) and T c (P) are the fuel and coolant temperatures at power P
Typical values
• T emperature Defect
• P ower Defect
• Good exercise: Lewis 9 . 4
Excess Reactivity
• Defined as the value of rho if all control poisons and rods were removed from the core
– Large excess reactivity are avoided because they need lots of poison to compensate at BOC (beginning of cycle) and require extra care
– Creates dangerous scenarios (e . g . high worth control rods become a problem if ejected)
– Strict limits are thus p laced on excess reactivit y and on the reactivity limits of control devices
• Large amount of small control rods
coefficients are nice
• T emperature feedback causes excess reactivity t o d e c r e a s e
• N egative temperature
– N eed to pull out control rods
from a stability and • If you shutdown, temperature
safety point of v i e w , large negative values can c r e a t e excess reactivity problems
• P l o t d e p i c t s
– C old shutdown (a)
– C old critical (b)
– H ot zero power critical
– Full power (d)
Shutdown mar gin
ex
(c)
decreases and excess reactivity is
increased
– N eed to insert control rods as you reduce power
T emperature defect
b
a
Power defect
c
d
BOL
T ime
EOL
Image by MIT OpenCourseWare.
Shutdown Margin
• A minimum shutdown margin is imposed by the NRC
– R eac ti v it y requ i re d t o s h u td own th e reac t or no ma tt er i n w hi c h con diti on (cold critical is the one with the most excess reactivity)
– T he stuck rod criteria is usually applied
– N ormally 1-5% of excess reactivity
• Going from curve a to b removes the excess margins to get to cold critical
• As the core is heated, the excess r eactivity curve goes from b to c, with the d ifference being the t emperature defect
– S low temperature increase to reduce mechanical stresses on pipes and pressure vessel
• As the reactor goes up in power, we approach curve d
– R ema i n i ng excess reac ti v it y i s w h a t a ll ows th e core t o opera t e f or a given cycle
– T ypical LWR cycle 1-2 years
• C ore designers try to predict excess reactivity curves
– Schedule outages
– Prepare reloading
• C ores are usually reloaded in 3-4 batches, thus in a PWR you re p lace about 60 assemblies at each c y cle
• T ypical assemblies will thus stay in the core for 3 cycles or 4.5 years
• F uel is then sent to spent fuel pools for at least 5 years
• P oo l con fi gura ti on i s i mpor t an t t o avo id cr iti ca lit y acc id en t s
• W hen pool is full, oldest spent fuel elements are put in dry casks
• If they fall short on reactivity, they can reduce power to reduce temperature and increase excess reactivity
• If they under predict the excess reactivity, it indicates that they loaded more fresh fuel bundles than they needed
– R eactor is still shutdown on schedule due to mobilization of workforce
– $$$
• Outages usually last 3 - 4 w eeks
Reactor Transients
• If rapid changes of power occur, steady - state temperatures cannot be used
– Rod e j ection
– Loss of coolant
– Loss of flow
• We can develop a simple reactor d y namics model based on the kinetics relation, and the temperature transient models
• P ower
d P ( t ) = [ ( t ) - ] P ( t ) +
C ~ ( t )
dt
i i i
• Precursors
d C ~ ( t ) = i P ( t ) - C ~ ( t ) i = 1, 2, 3, 4, 5, 6
dt i i i
• Fuel temperature
d T f ( t ) = 1
P ( t ) - 1
[ T f ( t ) - T i ]
dt M f c f ~
• Coolant temperature T c ( t ) = T i + 2 R f
1
Wc p
T f ( t )
Feedback effects
• T h e r e a c t i v i t y w i l l a l s o h a v e t o i n c l u d e the temperature feedback effects
( t ) = i ( t ) - | f | [ T f ( t ) - T f (0)] - | c | [ T c ( t ) - T c (0)]
• If the reactor is initially critical at power P 0 we can evaluate the temperatures and precursor concentrations using the steady- state relations
Demo – Step insertion
• Beta = 0 . 0065
• F u ll power = 3000 MWth
– T inlet = 300 C
– T fuel = 1142 C
Step of 0 . 2$ -
Full Power
Neutr on population over all time
Neutr on population over all time
5000 3800
4500 3600
4000 3400
3500
3000
0
1 2 3 4 5 6 7 8 9
10
3200
3000
0 1 2 3 4 5 6 7 8 9 10
Precursor Population
2.4
x 10 7
x 10 7
Precursor Population
2.2
2
2.02
2
1.98
1.96
1.8 0
1
2 3 4 5 6 7 8 9 10
1.94
0 1 2 3 4 5 6 7 8 9 10
Feedback
No Feedback
• T fuel at 10 seconds = 1173 C
Image by MIT OpenCourseWare.
• Prompt jump b r i n g s p o w e r t o 3 7 0 0 M W t h
– S tabilizes to 3100 MWth with feedback
Step of 0 . 2$ - Low P o w e r ( 1 M W t h )
Neutr on population over all time
1.8
Neutr on population over all time
150
1.6
100
1.4
1.2
50
1
0
1
2
3
4
5
6
7
8
9
10
0
0 100 200 300 400 500 600 700 800 900 1000
8000
Pr ecursor population
7500
x 10
8
6
5
Pr ecursor population
7000
4
6500
2
6000
0
1
2
3
4
5
6
7
8
9
10
0
0 100 200 300 400 500 600 700 800 900 1000
Feedback - 1000s
Feedback - 10s
Image by MIT OpenCourseWare.
• F uel temperature eventually reaches 333 C
• P ower eventually stabilizes to 120 MWth
Step of 1$ at F u l l p o w e r
10
8
6
4
2
x 10 5
Neutr on population over all time
x 10
3
4
Neutr on population over all time
2
1
0
0 0.5 1 1.5 2 2.5 3 3.5 4 4.5
5
0
0 0.5 1 1.5 2 2.5 3 3.5 4 4.5 5
Pr ecursor population
3
x 10 17
x 10
2.2
7
Pr ecursor population
2
2.1
1
2.0
0
0 0.5 1 1.5 2 2.5 3 3.5 4 4.5
5
1.9
0 0.5 1 1.5 2 2.5 3 3.5 4 4.5 5
Feedback
No Feedback
• P ower spikes to 27500 MWth
• Stabilizes t o 3 5 6 7 M W t h
Image by MIT OpenCourseWare.
• F uel temperature reaches 1293 C
R a m p i n s e r t i o n 1 $ / s w i t h F eedback
8000
Neutr on population over all time
15000
Neutr on population over all time
6000
10000
4000
5000
2000
0 0.5 1 1.5 2 2.5 3 3.5 4 4.5
5
0
0 0.5 1 1.5 2 2.5 3 3.5 4 4.5 5
Pr ecursor population
2.6
x 10 7
6 x 10 6
Pr ecursor population
2.4
4
2.2
2.0
2
1.8
0 0.5 1 1.5 2 2.5 3 3.5 4 4.5 5
0
0 0.5 1 1.5 2 2.5 3 3.5 4 4.5 5
Low Power
Full Power
• F uel temperature increase is greater at high power
Image by MIT OpenCourseWare.
• At low power, negative reactivity feedback is too slow, thus reactor reaches prompt critical, until temperature increases
• B o t h s i t ua t i on converge t o t h e same power even t ua l l y
Shutdown ( - 5 * B e t a )
3000
Neutr on population over all time
3000
Neutr on population over all time
2000
2000
1000
1000
0
0
0
1 2 3 4
5 6
7 8
9
10
0
1 2
3
4
5
6 7
8 9 10
2
x 10 7
Pr ecursor population
2
x 10 7
Pr ecursor population
1.5
1.5
1
0
1 2 3 4
5 6
7 8
9
10
1
0
1 2
3
4
5
6
7
8 9 10
Feedback
No Feedback
Image by MIT OpenCourseWare.
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22.05 Neutron Science and Reactor Physics
Fall 20 09
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