Chapter 8 Energy Transport

Background

Chapter 5 dealt with how the neutron population varies in time

Chapter 6 and 7 dealt with the s patial distribution of neutrons in the core

It was determine that a critical reactor could operate at any power level and that the equilibrium would hold

N o t en ti re l y t rue !

A t high power levels, temperature changes will create important transients

Objectives

Find simple expressions to approximate fuel temperature and coolant temperature in a reactor

S teady-state temperatures

Transients

D etermine temperature effect on reactivity

C o r e Power D e n s i t y

P''' = P / V

P ’’’ is the power density

P i s the t o t a l c o r e power

V is the core volume

P o w e r Peaking F a c t o r

F q = P m '' ' ax / P'''

F q is the power peaking factor

P ’’’ max i s the m a x i m u m p o w e r d e n s i t y i n the core

P = P ' m ''

ax V

F q

We can combine the two p revious e q uations and find the above relation

Cores are designed to operate at a given power P

Maximizing the ratio P’’’max / Fq will allow for smaller r e a c t o r d e s i g n a t g iven p o w e r P

Reduces construction cost

Main job of reactor physicist is to maximize this ratio

Control r ods

New designs

Varying enrichment

P ’’’ max depends primarily on material properties

Temperature and pressure that can be tolerated by fuel, coolant, structure

Fq can be lowered by playing with enrichment loading, position of control

rods ,

poisons ,

reflector ,

f r (r)

f q (r ,z) = f r (r)f z (z)

f z (z)

For a uniform bare reactor F q = F r F z

From chapter 7, we’ve seen the solution for such a reactor

F r = 2.32

F z = 1.57

More complicated geometries will have higher peaking due to local variations

Image by MIT OpenCourseWare.

Simple heat transfer on fuel e l ement

Define q has the linear heat rate (kW/m)

T hermal power produced per unit length

P ’’’ = q / A cell element

where A cell is the area of the fuel

q’ = PF q A cell / V = PF q / NH N: Number of fuel pins

H: Height of the core

Steady - s t a t e temperatures

T e m p e r a t u r e d r o p f r o m f u e l t o coolant i s proportional to linear heat rate

T fe ( r , z ) - T c ( r ,z ) = R f ' e q ' ( r ,z )

R’ fe is the fuel element thermal resistance, details of which are found in Appendix D

f unc ti on o f th e th erma l con d uc ti v i t y o f th e f ue l an d

the cladding as well as the heat transfer coefficient

If we average over the volume

T f - T c = R f P

w h ere

NH

R f = 1 R ' fe

It should be noted that w h e n a v e r a g i n g q using the previous relation q’ = PF q / NH, we

must note that the avera g e core factor is 1.

p eakin g

We know Rf and P, but we need more information to evalute Tf and Tc

Coolant heat balance

Outlet temperature = T 0

W ch c p [ T 0 ( r ) - T i ] =

H/ 2

-H/ 2

q' ( r , z' ) dz'

_ Replacing q' and solving for T 0

Flow rate = W ch

T 0 ( r ) =

1 P Wc p NH

f r ( r )

H/ 2

-H/ 2

f z (z) dz + T i

_ Define total core flow rate

W = NW ch

Inlet temperature = T i

Image by MIT OpenCourseWare.

We get

Wc

T 0 ( r ) =

1 Pf r ( r ) + T i p

If we average radially

T 0 =

1 P + T i p

Wc

Average coolant temperature

T c =

1 ( T o + T i )

2

We can than get an expression for the coolant

tem p erature

1 P + T

T c = i

2Wc p

And we can replace it in our previous expression

2Wc p

T f = ( R f + 1

P + T i

Fuel Thermal transients

If c o o l i n g is t u r n e d o f f , w e c a n approximate that the fuel will heat up adiabatically

M f c f

d T f ( t ) = P ( t ) - 1 [ T f ( t ) - T c (t)]

R

dt

f

M f is the total fuel mass c f is the fuel specific heat

B o u n d i n g c a se s

Steady-state d/dt =0 P = ( T f - T c )/ R f

dt

N o c o o l i n g ( R f tends to infinity) M f c f d T f ( t ) = P ( t )

All the power stays in the fuel, fuel temperature increases and can eventuall y lead to meltin g

More convenient form

d T f ( t ) = 1 P ( t ) - 1 [ T f ( t ) - T c ( t )]

dt M f c f

IJ i s t h e core t h erm a l t i me constant

Coolant thermal transient

C o n s e v a t i o n e q u a t i o n in the c o o l a n t

M c c p

d T c ( t ) = 1

dt

R

f

[ T f ( t ) - T c ( t )] - 2 Wc p [ T c ( t ) - T i ]

R

Heating term 1 [ T f ( t )- T c ( t )]

f

Cooling term 2 Wc p [ T c ( t )- T i ]

W e ca n r e writ e h as

c

d T ( t ) = 1

dt '

[ T ( t ) - T ( t )] - 1

f c

''

[ T c ( t ) - T i ]

where

' =

M c c p

M f c f

and

'' =

M c c p

2 Wc p

C oolant usuall y follows fuel surface transient quite rapidly

W e c a n ignore the energy storage t e r m of the

coolant equation

T c ( t ) =

1 1 + 2 R f Wc p

[2 R f Wc p T i + T f ( t )]

C ombining with the fuel transient expression

f

d T ( t ) =

dt

1 P ( t ) - 1

M f c f ~

[ T f

( t ) - T i ]

Chapter 9 Reactivity Feedback

Background

Temperature increase w ill create feedback mechanisms in the reactor

Do pp ler broadenin g

T hermal expansion

Densit y cha n g es which will induce s p ectral shifts

T hese changes will impact the reactivity, thus causing transients

Reactivity Coefficients

D y n a m i c r e a c t i v i t y was d e f i n e d b y

( t ) = k ( t ) - 1

k ( t )

We can relate a change in reactivity to a chan g e in k

dp = dk/k 2 ~

dk/k

= d (ln k )

The advantage is that we change a multiplication of terms into a sum of terms

F u e l Temperature C oefficient

D oppler broadening of the resonance capture cross-section of U-238 is the dominant effect in LWR reactors

Lots of U-238 (red) present

S imilar effect with Th-232 (green)

Image removed due to copyright restrictions.

Fuel Temperature C oefficient

E ffect is felt in resonance esca p e p robabilit y (p)

N o effect on ε ,because

M inor effect on η and f

E specially in the presence of Pu-239

D oppler effect arises from the temperature d epen d ence o f th e cross-sec ti on on th e re l a ti ve speed between neutron and nucleus

Resonances are s meared in energy has temperature increases.

Thermal resonances are more important

F u e l Temperature C o e fficient

W e c a n a p p r o x i m a t e i t b y

f =

1 k ~

1 p

k T f

p T f

Y ou can eva l ua t e i t us i ng f ormu l as f rom Chapter 4 used to determine p (see book)

O r, you can a l so run s i mu l a t i ons a t different fuel temperatures and compare the e s t i m a t e o f the e i g e n v a l u e

M o d e r a t o r Temperature Coefficient

We s e e k to evaluate

m = 1 k

k T m

T he biggest impact of the moderator temperature comes f r o m a s s o c i a t e d c h a n g e s in density

A s temperature increases, moderator ( and coolant ) will see a decrease in their density

Less water molecules, means less moderation, leading to a s p e c t r a l s h i f t

M o d e r a t o r Temperature Coefficient

D ecrease in slowin g down efficienc y will lead to an increase in resonance absorption

V alue of p will decrease

Lower coolant density will also have an impact on the thermal utilization (f)

V alue of f will increase

F a s t f ission will increase slightly, but e ff ect is negligible

The combine effect is usually negative , but in

some reactors with solid moderators (i.e. graphite), the coefficient might be positive over certain temperature ranges .

Coolant Void Reactivity Coefficient

In LWRs and BWRs, this coefficient is alwa y s ne g ative

C oolant and moderator are the same, thus losing the coolant also implies loosing all the moderation

In CANDU and RBMK , this coefficient is p ositive

Loosing the coolant as very little impact on the moderation

C auses slight increase in fast fission

C auses sli g ht increase in resonance esca p e p robabilit y

Before Chernobyl, void reactivity coefficient of RBMK was 4.7 beta, after re-design it was lowered to 0.7 beta

C ANDU have a very small positive reactivity coefficient that can be controlled easily

Fast Reactor Coefficients

Leakage plays a more important role in fast reactor transients

D ecreasing density will make the spectrum harder

Larger value of η , thus increase in k

Migration length would also increase

More leakage , th u s decreasing k

Overall effect is usually positive

Doppler effect is smaller in m agnitude

Thermal resonances are more affected

I s o t h e r m a l T emperature Coefficient

In man y reactors, the entire core is brou g ht ver y slowly from room temperature to the operating inlet coolant temperature

R e a c t o r a t l o w p o w e r

E xternal heat source

D ecay heat

R easona b l e approx i ma ti on i s t o assume th a t th e core behaves isothermally

T f = T c = T i

We can thus define the isothermal temperature

coefficient

d fb 1 k 1 k

= = +

T = f c

T dT k T f k T c

Temperature D e f e c t

This coefficient a l l o w s u s t o e s t i m a t e the amount of reactivity needed to maintain c r i t i c a l i t y a t h i g h t e m p e r a t u r e ( h o t z e r o power)

T h i s r e a c t i v i t y i s o b t a i n e d b y i n t e g r a t i n g the isothermal temperature coefficient from r o o m t e m p e r a t u r e t o hot t e m p e r a t u r e

D T = T i T ( T ) dT

T r

P o w e r c o e f f i c i e n t

A far m o r e u s e f u l c o e f f i c i e n t , i t t a k e s i n t o account impact of temperature changes when r e a c t o r i s o p e r a t i n g a t f u l l power

d fb

1 k

dT f 1 k

dT c

P = dP

=

k T f

dP + k

T c dP

If we assume that power changes are slow compared to the time required for heat removal, we can use the steady-state temperature profiles from Chapter 8 and derive them with respect to Power

T c =

2 1 P + T i

d T c = 1

Wc p

dP 2 Wc p

T f = R f + 2

1 P + T i d T f = R f + 1

( Wc p ) d P 2 Wc p

P o w e r c o e f f i c i e n t

T h e p o w e r coefficient i s t h u s e x p r e s s e d i n

terms of both the fuel coefficient and the moderator coefficient

2 Wc p

k

T f

2 Wc p

k

T c

P = ( R f + 1 ) 1 k + 1 1 k

P = R f f + (2 Wc p ) -1 ( f + c )

T h u s , a s p o w e r i s i n c r e a s e d , p o s i t i v e reactivity is required to overcome negative c o e f f i c i e n t s a n d m a i n t a i n c r i t i c a l i t y

P o w e r D e f e c t

A s p o w e r i n c r e a s e s t o its o p e r a t i n g level, additional negative reactivity is introduced b y an increase in tem p erature

We can evaluate the power defect by the followin g

D p = T f ( p )

T i f

( T f

) dT f +

T c ( p ) e ( T c ) dT c

T i

where T f (P) and T c (P) are the fuel and coolant temperatures at power P

Typical values

T emperature Defect

P ower Defect

Good exercise: Lewis 9 . 4

Excess Reactivity

Defined as the value of rho if all control poisons and rods were removed from the core

Large excess reactivity are avoided because they need lots of poison to compensate at BOC (beginning of cycle) and require extra care

Creates dangerous scenarios (e . g . high worth control rods become a problem if ejected)

Strict limits are thus p laced on excess reactivit y and on the reactivity limits of control devices

Large amount of small control rods

coefficients are nice

T emperature feedback causes excess reactivity t o d e c r e a s e

N egative temperature

N eed to pull out control rods

from a stability and If you shutdown, temperature

safety point of v i e w , large negative values can c r e a t e excess reactivity problems

P l o t d e p i c t s

C old shutdown (a)

C old critical (b)

H ot zero power critical

Full power (d)

Shutdown mar gin

ex

(c)

decreases and excess reactivity is

increased

N eed to insert control rods as you reduce power

T emperature defect

b

a

Power defect

c

d

BOL

T ime

EOL

Image by MIT OpenCourseWare.

Shutdown Margin

A minimum shutdown margin is imposed by the NRC

R eac ti v it y requ i re d t o s h u td own th e reac t or no ma tt er i n w hi c h con diti on (cold critical is the one with the most excess reactivity)

T he stuck rod criteria is usually applied

N ormally 1-5% of excess reactivity

Going from curve a to b removes the excess margins to get to cold critical

As the core is heated, the excess r eactivity curve goes from b to c, with the d ifference being the t emperature defect

S low temperature increase to reduce mechanical stresses on pipes and pressure vessel

As the reactor goes up in power, we approach curve d

R ema i n i ng excess reac ti v it y i s w h a t a ll ows th e core t o opera t e f or a given cycle

T ypical LWR cycle 1-2 years

C ore designers try to predict excess reactivity curves

Schedule outages

Prepare reloading

C ores are usually reloaded in 3-4 batches, thus in a PWR you re p lace about 60 assemblies at each c y cle

T ypical assemblies will thus stay in the core for 3 cycles or 4.5 years

F uel is then sent to spent fuel pools for at least 5 years

P oo l con fi gura ti on i s i mpor t an t t o avo id cr iti ca lit y acc id en t s

W hen pool is full, oldest spent fuel elements are put in dry casks

If they fall short on reactivity, they can reduce power to reduce temperature and increase excess reactivity

If they under predict the excess reactivity, it indicates that they loaded more fresh fuel bundles than they needed

R eactor is still shutdown on schedule due to mobilization of workforce

$$$

Outages usually last 3 - 4 w eeks

Reactor Transients

If rapid changes of power occur, steady - state temperatures cannot be used

Rod e j ection

Loss of coolant

Loss of flow

We can develop a simple reactor d y namics model based on the kinetics relation, and the temperature transient models

P ower

d P ( t ) = [ ( t ) - ] P ( t ) +

C ~ ( t )

dt

i i i

Precursors

d C ~ ( t ) = i P ( t ) - C ~ ( t ) i = 1, 2, 3, 4, 5, 6

dt i i i

Fuel temperature

d T f ( t ) = 1

P ( t ) - 1

[ T f ( t ) - T i ]

dt M f c f ~

Coolant temperature T c ( t ) = T i + 2 R f

1

Wc p

T f ( t )

Feedback effects

T h e r e a c t i v i t y w i l l a l s o h a v e t o i n c l u d e the temperature feedback effects

( t ) = i ( t ) - | f | [ T f ( t ) - T f (0)] - | c | [ T c ( t ) - T c (0)]

If the reactor is initially critical at power P 0 we can evaluate the temperatures and precursor concentrations using the steady- state relations

Demo Step insertion

Beta = 0 . 0065

F u ll power = 3000 MWth

T inlet = 300 C

T fuel = 1142 C

Step of 0 . 2$ -

Full Power

Neutr on population over all time

Neutr on population over all time

5000 3800

4500 3600

4000 3400

3500

3000

0

1 2 3 4 5 6 7 8 9

10

3200

3000

0 1 2 3 4 5 6 7 8 9 10

Precursor Population

2.4

x 10 7

x 10 7

Precursor Population

2.2

2

2.02

2

1.98

1.96

1.8 0

1

2 3 4 5 6 7 8 9 10

1.94

0 1 2 3 4 5 6 7 8 9 10

Feedback

No Feedback

T fuel at 10 seconds = 1173 C

Image by MIT OpenCourseWare.

Prompt jump b r i n g s p o w e r t o 3 7 0 0 M W t h

S tabilizes to 3100 MWth with feedback

Step of 0 . 2$ - Low P o w e r ( 1 M W t h )

Neutr on population over all time

1.8

Neutr on population over all time

150

1.6

100

1.4

1.2

50

1

0

1

2

3

4

5

6

7

8

9

10

0

0 100 200 300 400 500 600 700 800 900 1000

8000

Pr ecursor population

7500

x 10

8

6

5

Pr ecursor population

7000

4

6500

2

6000

0

1

2

3

4

5

6

7

8

9

10

0

0 100 200 300 400 500 600 700 800 900 1000

Feedback - 1000s

Feedback - 10s

Image by MIT OpenCourseWare.

F uel temperature eventually reaches 333 C

P ower eventually stabilizes to 120 MWth

Step of 1$ at F u l l p o w e r

10

8

6

4

2

x 10 5

Neutr on population over all time

x 10

3

4

Neutr on population over all time

2

1

0

0 0.5 1 1.5 2 2.5 3 3.5 4 4.5

5

0

0 0.5 1 1.5 2 2.5 3 3.5 4 4.5 5

Pr ecursor population

3

x 10 17

x 10

2.2

7

Pr ecursor population

2

2.1

1

2.0

0

0 0.5 1 1.5 2 2.5 3 3.5 4 4.5

5

1.9

0 0.5 1 1.5 2 2.5 3 3.5 4 4.5 5

Feedback

No Feedback

P ower spikes to 27500 MWth

Stabilizes t o 3 5 6 7 M W t h

Image by MIT OpenCourseWare.

F uel temperature reaches 1293 C

R a m p i n s e r t i o n 1 $ / s w i t h F eedback

8000

Neutr on population over all time

15000

Neutr on population over all time

6000

10000

4000

5000

2000

0 0.5 1 1.5 2 2.5 3 3.5 4 4.5

5

0

0 0.5 1 1.5 2 2.5 3 3.5 4 4.5 5

Pr ecursor population

2.6

x 10 7

6 x 10 6

Pr ecursor population

2.4

4

2.2

2.0

2

1.8

0 0.5 1 1.5 2 2.5 3 3.5 4 4.5 5

0

0 0.5 1 1.5 2 2.5 3 3.5 4 4.5 5

Low Power

Full Power

F uel temperature increase is greater at high power

Image by MIT OpenCourseWare.

At low power, negative reactivity feedback is too slow, thus reactor reaches prompt critical, until temperature increases

B o t h s i t ua t i on converge t o t h e same power even t ua l l y

Shutdown ( - 5 * B e t a )

3000

Neutr on population over all time

3000

Neutr on population over all time

2000

2000

1000

1000

0

0

0

1 2 3 4

5 6

7 8

9

10

0

1 2

3

4

5

6 7

8 9 10

2

x 10 7

Pr ecursor population

2

x 10 7

Pr ecursor population

1.5

1.5

1

0

1 2 3 4

5 6

7 8

9

10

1

0

1 2

3

4

5

6

7

8 9 10

Feedback

No Feedback

Image by MIT OpenCourseWare.

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22.05 Neutron Science and Reactor Physics

Fall 20 09

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